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(C) The number of $\pi$-bonds in the structures are as follows:$1.$ $H_2SO_3$ (Sulfurous acid): It has one $S=O$ double bond,so it contains $1$ $\pi$-

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$H_2S_2O_7 > H_2SO_4 > H_2SO_3$

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(C) The number of $\pi$-bonds in the structures are as follows:$1.$ $H_2SO_3$ (Sulfurous acid): It has one $S=O$ double bond,so it contains $1$ $\pi$-bond.$2.$ $H_2SO_4$ (Sulfuric acid): It has two $S=O$ double bonds,so it contains $2$ $\pi$-bonds.$3.$ $H_2S_2O_7$ (Pyrosulfuric acid): It has four $S=O$ double bonds (two on each sulfur atom),so it contains $4$ $\pi$-bonds.Therefore,the correct decreasing sequence of the number of $\pi$-bonds is $H_2S_2O_7 (4) > H_2SO_4 (2) > H_2SO_3 (1)$.

The correct sequence of decreasing number of $\pi$-bonds in the structures of $H_2SO_3$,$H_2SO_4$,and $H_2S_2O_7$ is:

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