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(D) The first step is nitration because the nitro group $(-NO_2)$ is a meta-directing group,which is required to place the bromine atom at the $m$-pos

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nitration,bromination,reduction

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(D) The first step is nitration because the nitro group $(-NO_2)$ is a meta-directing group,which is required to place the bromine atom at the $m$-position relative to the amino group.Next,bromination of nitrobenzene is performed to introduce the bromine atom at the $m$-position.Finally,the reduction of the nitro group to an amino group $(-NH_2)$ yields $m$-bromoaniline.The reaction sequence is:Benzene $\xrightarrow{	ext{nitration}}$ Nitrobenzene $\xrightarrow{	ext{bromination}}$ $m$-Bromonitrobenzene $\xrightarrow{	ext{reduction}}$ $m$-Bromoaniline

The correct sequence of reactions to be performed to convert benzene into $m$-bromoaniline is

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