The correct set of four quantum numbers for t | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The electronic configuration of potassium $(Z=19)$ is $1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{6} 4s^{1}$.The outermost electron is in the $4s$ orbital.Fo

Vedclass · Accepted Answer

$4, 0, 0, \frac{1}{2}$

Vedclass · Answer

(C) The electronic configuration of potassium $(Z=19)$ is $1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{6} 4s^{1}$.The outermost electron is in the $4s$ orbital.For the $4s$ orbital,the principal quantum number $(n) = 4$.The azimuthal quantum number $(l)$ for an $s$-orbital is $0$.The magnetic quantum number $(m_l)$ is $0$.The spin quantum number $(m_s)$ is $+\frac{1}{2}$ (or $-\frac{1}{2}$).Thus,the correct set of quantum numbers is $4, 0, 0, \frac{1}{2}$.

The correct set of four quantum numbers for the outermost electron of potassium $(Z=19)$ is

Similar Questions

What is the number of unpaired electrons in a ferrous ion $(Fe^{2+})$?

The order of increasing energies of the orbitals follows:

From the given sets of quantum numbers,the one that is inconsistent with the theory is:

Paramagnetic substances must contain .....

If $n + l = 6$,then the total possible number of subshells would be

Vedclass Test Series

Exam Paper Generator

Online Exam Module