The correct set of four quantum numbers for t | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The atomic number of rubidium $(Rb)$ is $37$.The electronic configuration of $Rb$ is $[Kr] 5s^1$.The valence electron is in the $5s$ orbital.For t

Vedclass · Accepted Answer

$n=5, l=0, m=0, s=+\frac{1}{2}$

Vedclass · Answer

(A) The atomic number of rubidium $(Rb)$ is $37$.The electronic configuration of $Rb$ is $[Kr] 5s^1$.The valence electron is in the $5s$ orbital.For the $5s$ orbital:Principal quantum number $(n) = 5$.Azimuthal quantum number $(l) = 0$ (for $s$-orbital).Magnetic quantum number $(m) = 0$.Spin quantum number $(s) = +\frac{1}{2}$ or $-\frac{1}{2}$.Thus,the correct set is $(n=5, l=0, m=0, s=+\frac{1}{2})$.

The correct set of four quantum numbers for the valence electron of rubidium atom $(Z=37)$ is:

Similar Questions

Total number of electrons in $Cu$ atom having $m_l = 0$.

The orbital angular momentum of an electron in $2s$-orbital is

Which of the following sets of species has the $3^{rd}$ principal energy level $(n=3)$ completely filled?

Which set of quantum numbers for an electron of an atom is not possible?

For $p$-orbital,the magnetic quantum number has value

Vedclass Test Series

Exam Paper Generator

Online Exam Module