The correct set of oxidation numbers of N in | vedclass

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(D) The compound $NH_4NO_2$ is an ionic salt consisting of the ammonium ion $(NH_4^+)$ and the nitrite ion $(NO_2^-)$.In $NH_4^+$,let the oxidation nu

Vedclass · Accepted Answer

$-3, +3$

Vedclass · Answer

(D) The compound $NH_4NO_2$ is an ionic salt consisting of the ammonium ion $(NH_4^+)$ and the nitrite ion $(NO_2^-)$.In $NH_4^+$,let the oxidation number of $N$ be $x$. Thus,$x + 4(+1) = +1$,which gives $x = -3$.In $NO_2^-$,let the oxidation number of $N$ be $y$. Thus,$y + 2(-2) = -1$,which gives $y - 4 = -1$,so $y = +3$.Therefore,the oxidation numbers of $N$ are $-3$ and $+3$.

The correct set of oxidation numbers of $N$ in $NH_4NO_2$ is

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