The correct statement$(s)$ about the compound given below is(are):
$A$. The compound is optically active
$B$. The compound possesses centre of symmetry
$C$. The compound possesses plane of symmetry
$D$. The compound possesses axis of symmetry
$A$. The compound is optically active
$B$. The compound possesses centre of symmetry
$C$. The compound possesses plane of symmetry
$D$. The compound possesses axis of symmetry
- A$B, C$
- B$A, C$
- C$A, B$
- D$A, D$
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Similar Questions
What is the absolute configuration of the following molecules? ($NS =$ the molecule has no stereocenter) Note: For the purpose of this question only,the order of stereocenters is not specified; i.e.,$R, S = S, R$.
$(I)$ || $(II)$ || $(III)$ || $(IV)$
$(I)$ || $(II)$ || $(III)$ || $(IV)$
Difficult
View SolutionMatch List-$I$ with List-$II$.
List-$I$ Isomeric pairs List-$II$ Type of isomers $A$. Propanamine and $N$-Methylethanamine $I$. Metamers $B$. Hexan-$2$-one and Hexan-$3$-one $II$. Positional isomers $C$. Ethanamide and Hydroxyethanimine $III$. Functional isomers $D$. $o$-nitrophenol and $p$-nitrophenol $IV$. Tautomers
Choose the correct answer from the options given below:
| List-$I$ Isomeric pairs | List-$II$ Type of isomers |
| $A$. Propanamine and $N$-Methylethanamine | $I$. Metamers |
| $B$. Hexan-$2$-one and Hexan-$3$-one | $II$. Positional isomers |
| $C$. Ethanamide and Hydroxyethanimine | $III$. Functional isomers |
| $D$. $o$-nitrophenol and $p$-nitrophenol | $IV$. Tautomers |
Choose the correct answer from the options given below:
DifficultJEE MAIN 2023
View SolutionWhich of the following pairs are not diastereomers?
Difficult
View SolutionWhich of the following molecules does not contain two chiral carbon atoms?
Easy
View SolutionWhich energy diagram best represents the given reaction?
Difficult
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