The correct statement among the following is:

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(A) In $(SiH_3)_3N$,the lone pair of electrons on the nitrogen atom is involved in $p\pi-d\pi$ back-bonding with the vacant $d$-orbitals of the silico

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$(SiH_3)_3N$ is planar and less basic than $(CH_3)_3N$

Vedclass · Answer

(A) In $(SiH_3)_3N$,the lone pair of electrons on the nitrogen atom is involved in $p\pi-d\pi$ back-bonding with the vacant $d$-orbitals of the silicon atoms. This results in the molecule adopting a planar geometry ($sp^2$ hybridization). Because the lone pair is delocalized into the $d$-orbitals of silicon,it is not readily available for donation,making $(SiH_3)_3N$ much less basic than $(CH_3)_3N$,where the lone pair is localized on the nitrogen atom.

Column-$I$	Column-$II$
$(P)$ $\underline PCl_5 \to PCl_3 + Cl_2$	$(i)$ Change in hybridisation
$(Q)$ $\underline SO_3 \to \underline SO_2 + \frac{1}{2}O_2$	$(ii)$ Change in bond angle
$(R)$ $\underline NH_3 + H^{+} \to \underline NH_4^+$	$(iii)$ Change in shape
$(S)$ $H_2\underline O + H^{+} \to H_3\underline O^{+}$	$(iv)$ Change in oxidation state

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Select the $CORRECT$ statement.

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