The correct structural formula of butanoic acid is
- A$CH_2=CH-CH_2-COOH$
- B$CH_3-CH_2-CH_2-COOH$
- C$CH_3-CH_2-CH_2-CH_2-OH$
- D$CH_3-CH_2-CH_2-CH_2-CH_2-COOH$
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View SolutionMatch the reactions given in Column $(A)$ with the names given in Column $(B).$
Column $(A)$ Column $(B)$ $(a)$ $CH_{3}OH + CH_{3}COOH \xrightarrow{H^{+}} CH_{3}COOCH_{3} + H_{2}O$ $(i)$ Addition reaction $(b)$ $CH_{2}=CH_{2} + H_{2} \xrightarrow{Ni} CH_{3}-CH_{3}$ $(ii)$ Substitution reaction $(c)$ $CH_{4} + Cl_{2} \xrightarrow{\text{Sunlight}} CH_{3}Cl + HCl$ $(iii)$ Neutralisation reaction $(d)$ $CH_{3}COOH + NaOH \longrightarrow CH_{3}COONa + H_{2}O$ $(iv)$ Esterification reaction
| Column $(A)$ | Column $(B)$ |
| $(a)$ $CH_{3}OH + CH_{3}COOH \xrightarrow{H^{+}} CH_{3}COOCH_{3} + H_{2}O$ | $(i)$ Addition reaction |
| $(b)$ $CH_{2}=CH_{2} + H_{2} \xrightarrow{Ni} CH_{3}-CH_{3}$ | $(ii)$ Substitution reaction |
| $(c)$ $CH_{4} + Cl_{2} \xrightarrow{\text{Sunlight}} CH_{3}Cl + HCl$ | $(iii)$ Neutralisation reaction |
| $(d)$ $CH_{3}COOH + NaOH \longrightarrow CH_{3}COONa + H_{2}O$ | $(iv)$ Esterification reaction |
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