The critical angle between an equilateral pri | vedclass

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(B) For an equilateral prism,the angle of the prism $A = 60^o$. Given that the incident ray is perpendicular to the first refracting surface,the angle

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It is totally reflected on the second surface and emerges out perpendicularly from the third surface in air.

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(B) For an equilateral prism,the angle of the prism $A = 60^o$. Given that the incident ray is perpendicular to the first refracting surface,the angle of incidence $i = 0^o$. Therefore,the angle of refraction at the first surface $r_1 = 0^o$. The angle of incidence at the second surface is $r_2 = A - r_1 = 60^o - 0^o = 60^o$. The critical angle $C$ is given as $45^o$. Since the angle of incidence at the second surface $(60^o)$ is greater than the critical angle $(45^o)$,total internal reflection occurs at the second surface. The reflected ray then strikes the third surface (the base) at an angle of incidence of $30^o$ (calculated from the geometry of the triangle). Since $30^o Thus,the ray is totally reflected on the second surface and emerges out from the third surface.

The critical angle between an equilateral prism and air is $45^o$. If the incident ray is perpendicular to the refracting surface,then

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