The critical temperatures of gases A, B, C, a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The extent of physical adsorption of a gas on a solid surface is directly proportional to its ease of liquefaction.Easier liquefaction is indicate

Vedclass · Accepted Answer

$A$

Vedclass · Answer

(D) The extent of physical adsorption of a gas on a solid surface is directly proportional to its ease of liquefaction.Easier liquefaction is indicated by a higher critical temperature $(T_c)$.Therefore,gases with higher critical temperatures are adsorbed to a greater extent.The critical temperatures are: $B (630 \ K) > D (400 \ K) > C (261 \ K) > A (190 \ K)$.Thus,the order of adsorption is $B > D > C > A$.The gas with the lowest critical temperature will have the least amount adsorbed.Hence,gas $A$ has the least quantity adsorbed.

The critical temperatures of gases $A, B, C,$ and $D$ are $190 \ K, 630 \ K, 261 \ K,$ and $400 \ K$ respectively. The quantity of gas adsorbed per gram of charcoal at the same pressure is least for the gas:

Similar Questions

According to the Langmuir adsorption isotherm,the amount of gas adsorbed at very high pressures:

During the adsorption of krypton on activated charcoal at low temperature,which of the following thermodynamic conditions is true?

Which one of the following statements is not correct?

Which of the following statements is true for adsorption?

Which of the following is not a characteristic of chemisorption?

Vedclass Test Series

Exam Paper Generator

Online Exam Module