The current amplification factor of a transistor in common emitter configuration is $80$. If the emitter current is $2.43 \text{ mA}$, then the base current is (in $\mu \text{A}$)

In an $N-P-N$ transistor circuit,the collector current is $10 \ mA$. If $90\%$ of the electrons emitted reach the collector,then the emitter current $(I_E)$ and base current $(I_B)$ are respectively:

The power gain and voltage gain of a transistor connected in common emitter configuration are $1800$ and $60$ respectively. If the change in the emitter current is $0.62 \text{ mA}$, then the change in the collector current is: (in $\text{ mA}$)

In a common emitter amplifier,a.c. current gain is $40$ and input resistance is $2 \ k\Omega$. The load resistance is given as $10 \ k\Omega$. Then the voltage gain is

For a $CE$ amplifier,the current gain is $60$. If the load resistance is $5 \times 10^3 \ \Omega$ and the input resistance is $5 \times 10^2 \ \Omega$,then the voltage gain is .......

$A$ $npn$ transistor is connected in common emitter configuration in a given amplifier. $A$ load resistance of $800 \,\,\Omega$ is connected in the collector circuit and the voltage drop across it is $0.8 \,\, V$. If the current amplification factor is $0.96$ and the input resistance of the circuit is $192 \,\,\Omega$,the voltage gain and the power gain of the amplifier will respectively be