The current flowing in a copper voltameter is | vedclass

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(B) The total charge $Q$ passed through the circuit is given by $Q = I 	imes t$.Given $I = 1.6 \ A$ and $t = 1 \ 	ext{minute} = 60 \ s$,we have $Q =

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$3 	imes 10^{20}$

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(B) The total charge $Q$ passed through the circuit is given by $Q = I 	imes t$.Given $I = 1.6 \ A$ and $t = 1 \ 	ext{minute} = 60 \ s$,we have $Q = 1.6 	imes 60 = 96 \ C$.For the deposition of $Cu^{2+}$ ions,the reaction is $Cu^{2+} + 2e^- ightarrow Cu$.Each $Cu^{2+}$ ion requires $2$ electrons for deposition.If $n$ is the number of $Cu^{2+}$ ions,then the total charge $Q = n 	imes 2e$,where $e = 1.6 	imes 10^{-19} \ C$.Therefore,$n = \frac{Q}{2e} = \frac{96}{2 	imes 1.6 	imes 10^{-19}} = \frac{96}{3.2 	imes 10^{-19}} = 30 	imes 10^{19} = 3 	imes 10^{20}$ ions.

The current flowing in a copper voltameter is $1.6 \ A$. The number of $Cu^{2+}$ ions deposited at the cathode per minute are

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