The current flowing through an AC circuit is | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The given equation for current is $I = I_0 \sin(\omega t)$,where $I_0 = 5 	ext{ A}$ and $\omega = 120 \pi 	ext{ rad/s}$.The angular frequency $\

Vedclass · Accepted Answer

$\frac{1}{240} 	ext{ s}$

Vedclass · Answer

(D) The given equation for current is $I = I_0 \sin(\omega t)$,where $I_0 = 5 	ext{ A}$ and $\omega = 120 \pi 	ext{ rad/s}$.The angular frequency $\omega$ is related to the time period $T$ by the formula $\omega = \frac{2 \pi}{T}$.Substituting the value of $\omega$: $120 \pi = \frac{2 \pi}{T} \Rightarrow T = \frac{2 \pi}{120 \pi} = \frac{1}{60} 	ext{ s}$.The current reaches its peak value at $t = \frac{T}{4}$ (one-quarter of the time period).Therefore,the time taken is $t = \frac{1/60}{4} = \frac{1}{240} 	ext{ s}$.

The current flowing through an $AC$ circuit is given by $I = 5 \sin(120 \pi t) \text{ A}$. How long will the current take to reach the peak value starting from zero?

Similar Questions

What are $DC$ signals and $AC$ signals? Why do we prefer an $AC$ signal?

The $AC$ voltage across a resistance can be measured using a

The rms value of current $I_{\text{rms}}$ is

In general,in an alternating current circuit:

If an $AC$ main supply is given to be $220\,V$,the average $emf$ during a positive half cycle will be.....$V$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module