The current gain of a transistor in common em | vedclass

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(C) Given: Current gain $\beta = 80$, Collector resistance $R_C = 5 	ext{ k}\Omega$, Base resistance $R_B = 1 	ext{ k}\Omega$, Input voltage $V_I =

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$0.8$

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(C) Given: Current gain $\beta = 80$, Collector resistance $R_C = 5 	ext{ k}\Omega$, Base resistance $R_B = 1 	ext{ k}\Omega$, Input voltage $V_I = 2 	ext{ mV} = 2 	imes 10^{-3} 	ext{ V}$.The voltage gain $A_V$ for a common emitter transistor is given by the formula:$A_V = \frac{V_O}{V_I} = \beta 	imes \frac{R_C}{R_B}$Substituting the given values:$V_O = V_I 	imes \beta 	imes \frac{R_C}{R_B}$$V_O = (2 	imes 10^{-3} 	ext{ V}) 	imes 80 	imes \frac{5 	ext{ k}\Omega}{1 	ext{ k}\Omega}$$V_O = 2 	imes 10^{-3} 	imes 80 	imes 5$$V_O = 800 	imes 10^{-3} 	ext{ V}$$V_O = 0.8 	ext{ V}$.

The current gain of a transistor in common emitter configuration is $80$. The resistances in collector and base sides of the circuit are $5 \text{ k}\Omega$ and $1 \text{ k}\Omega$ respectively. If the input voltage is $2 \text{ mV}$, the output voltage is: (in $\text{ V}$)

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