The current in a coil changes from 2 ,A to 5 | vedclass

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(B) Change in current,$\Delta I = 5 \,A - 2 \,A = 3 \,A$.Time interval,$\Delta t = 0.3 \,s$.Induced emf,$e = 1.0 \,V$.The formula for induced emf in a

Vedclass · Accepted Answer

$100$

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(B) Change in current,$\Delta I = 5 \,A - 2 \,A = 3 \,A$.Time interval,$\Delta t = 0.3 \,s$.Induced emf,$e = 1.0 \,V$.The formula for induced emf in a coil due to self-inductance is given by $e = L \frac{dI}{dt}$.Considering the magnitude,$e = L \frac{\Delta I}{\Delta t}$.Substituting the values: $1.0 = L 	imes \frac{3}{0.3}$.$1.0 = L 	imes 10$.$L = \frac{1.0}{10} = 0.1 \,H$.Since $1 \,H = 1000 \,mH$,we have $L = 0.1 	imes 1000 \,mH = 100 \,mH$.

The current in a coil changes from $2 \,A$ to $5 \,A$ in $0.3 \,s$. The magnitude of emf induced in the coil is $1.0 \,V$. The value of self-inductance of the coil is (in $\,mH$)

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