The current in a diode is given by the equati | vedclass

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Question

(A) Given the equation for current: $I = e^{1000V/T} - 1$. Since $I = 11 	ext{ mA}$,we have $11 = e^{1000V/T} - 1$,which implies $e^{1000V/T} = 12$.

Vedclass · Accepted Answer

$\pm 0.4$

Vedclass · Answer

(A) Given the equation for current: $I = e^{1000V/T} - 1$. Since $I = 11 	ext{ mA}$,we have $11 = e^{1000V/T} - 1$,which implies $e^{1000V/T} = 12$. To find the error in current $\Delta I$,we differentiate the equation with respect to $V$: $\frac{dI}{dV} = \frac{d}{dV}(e^{1000V/T} - 1) = e^{1000V/T} \cdot \frac{1000}{T}$. Substituting $e^{1000V/T} = 12$ and $T = 300 	ext{ K}$: $\frac{dI}{dV} = 12 \cdot \frac{1000}{300} = 12 \cdot \frac{10}{3} = 40 	ext{ mA/V}$. The error in current is given by $\Delta I = \left| \frac{dI}{dV} ight| \cdot \Delta V$. Given $\Delta V = \pm 0.01 	ext{ V}$,we get $\Delta I = 40 \cdot 0.01 = 0.4 	ext{ mA}$. Thus,the error in current is $\pm 0.4 	ext{ mA}$.

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