The current passing through a conducting loop in the form of an equilateral triangle of side $4\sqrt{3} \text{ cm}$ is $2 \text{ A}$. The magnetic field at its centroid is $\alpha \times 10^{-5} \text{ T}$. The value of $\alpha$ is . . . . . . . (Given: $\mu_0 = 4\pi \times 10^{-7} \text{ SI units}$)

  • A
    $2\sqrt{3}$
  • B
    $\sqrt{3}$
  • C
    $3\sqrt{3}$
  • D
    $\frac{\sqrt{3}}{2}$

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