The de Broglie wavelength of the most energetic photoelectrons emitted from a photosensitive metal of work function $\phi$,when light of frequency $\nu$ is incident on it,is $\lambda$. Then $\nu =$ (where $h$ is Planck's constant and $m$ is the mass of the electron).

• A
  $\frac{2 \phi}{h} - \frac{h}{m \lambda^2}$
• B
  $\frac{2 \phi}{h} + \frac{h}{m \lambda^2}$
• C
  $\frac{\phi}{h} + \frac{h}{2 m \lambda^2}$
• D
  $\frac{\phi}{h} - \frac{h}{2 m \lambda^2}$