The decay of a proton to a neutron is:
- Anot possible as proton mass is less than the neutron mass
- Bpossible only inside the nucleus
- Cnot possible but neutron to proton conversion is possible
- Dalways possible as it is associated only with $\beta^{+}$ decay
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Similar Questions
$A$ radioactive nucleus with $Z$ protons and $N$ neutrons emits an $\alpha$-particle,$2\beta^-$-particles,and $2$ gamma rays. The number of protons and neutrons in the nucleus left after the decay,respectively,are:
Medium
View SolutionList-$I$ shows different radioactive decay processes and List-$II$ provides possible emitted particles. Match each entry in List-$I$ with an appropriate entry from List-$II$, and choose the correct option.
List-$I$ List-$II$ $(P)$ ${ }_{92}^{238} U \rightarrow{ }_{91}^{234} Pa$ $(1)$ $1 \alpha$ and $1 \beta^{+}$ $(Q)$ ${ }_{82}^{214} Pb \rightarrow{ }_{82}^{210} Pb$ $(2)$ $3 \beta^{-}$ and $1 \alpha$ $(R)$ ${ }_{81}^{210} Tl \rightarrow{ }_{82}^{206} Pb$ $(3)$ $2 \beta^{-}$ and $1 \alpha$ $(S)$ ${ }_{91}^{228} Pa \rightarrow{ }_{88}^{224} Ra$ $(4)$ $1 \alpha$ and $1 \beta^{-}$ $(5)$ $1 \alpha$ and $2 \beta^{+}$
| List-$I$ | List-$II$ |
| $(P)$ ${ }_{92}^{238} U \rightarrow{ }_{91}^{234} Pa$ | $(1)$ $1 \alpha$ and $1 \beta^{+}$ |
| $(Q)$ ${ }_{82}^{214} Pb \rightarrow{ }_{82}^{210} Pb$ | $(2)$ $3 \beta^{-}$ and $1 \alpha$ |
| $(R)$ ${ }_{81}^{210} Tl \rightarrow{ }_{82}^{206} Pb$ | $(3)$ $2 \beta^{-}$ and $1 \alpha$ |
| $(S)$ ${ }_{91}^{228} Pa \rightarrow{ }_{88}^{224} Ra$ | $(4)$ $1 \alpha$ and $1 \beta^{-}$ |
| $(5)$ $1 \alpha$ and $2 \beta^{+}$ |
$A$ nucleus with $Z = 92$ emits the following in a sequence: $\alpha, \beta^-, \beta^-, \alpha, \alpha, \alpha, \alpha, \alpha, \beta^-, \beta^-, \alpha, \beta^+, \beta^+, \alpha$. The $Z$ of the resulting nucleus is
MediumAIEEE 2003
View SolutionThe intensity of gamma radiation from a given source is $I$. On passing through $36 \, mm$ of lead,it is reduced to $\frac{I}{8}$. The thickness of lead which will reduce the intensity to $\frac{I}{2}$ will be......$mm$
DifficultAIEEE 2005
View SolutionAt a specific instant,the emission of a radioactive compound is deflected in a magnetic field. The compound can emit:
$(i)$ Electrons
$(ii)$ Protons
$(iii)$ $He^{2+}$
$(iv)$ Neutrons
The emission at that instant can be:
$(i)$ Electrons
$(ii)$ Protons
$(iii)$ $He^{2+}$
$(iv)$ Neutrons
The emission at that instant can be:
MediumAIEEE 2002
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