The decay of a radioactive material is shown | vedclass

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Question

(A) From the graph,we can observe the half-life $(T_{1/2})$ of the radioactive material. Initially,at $t = 0 \ h$,the amount of material is $100 \ kg$

Vedclass · Accepted Answer

$0.035$

Vedclass · Answer

(A) From the graph,we can observe the half-life $(T_{1/2})$ of the radioactive material. Initially,at $t = 0 \ h$,the amount of material is $100 \ kg$. The time taken for the material to reduce to half of its initial value $(50 \ kg)$ is $20 \ h$. Thus,the half-life $T_{1/2} = 20 \ h$.The decay constant $\lambda$ is related to the half-life by the formula: $\lambda = \frac{\ln(2)}{T_{1/2}}$.Substituting the value of $T_{1/2} = 20 \ h$:$\lambda = \frac{0.693}{20} \ h^{-1} = 0.03465 \ h^{-1} \approx 0.035 \ h^{-1}$.Therefore,the correct option is $A$.

The decay of a radioactive material is shown in the graph. From the graph,the decay constant of the material is nearly (in $h^{-1}$)

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