The decreasing order of basicity of the follo | vedclass

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(A) To determine the basicity,we look at the availability of the lone pair on the nitrogen atom:$1$. $(III)$ Cyclohexylamine: The nitrogen is attached

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$III > II > I > IV$

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(A) To determine the basicity,we look at the availability of the lone pair on the nitrogen atom:$1$. $(III)$ Cyclohexylamine: The nitrogen is attached to an $sp^3$ hybridized carbon. There is no resonance,and the alkyl group is electron-donating,making it the most basic.$2$. $(II)$ Pyridine: The lone pair is in an $sp^2$ orbital,which is more electronegative than $sp^3$,making it less basic than cyclohexylamine but more basic than aniline.$3$. $(I)$ Aniline: The lone pair on the nitrogen is involved in resonance with the benzene ring,significantly reducing its availability for protonation.$4$. $(IV)$ Pyrrole: The lone pair on the nitrogen is part of the aromatic sextet ($6\pi$ electrons),making it unavailable for protonation. Thus,it is the least basic.Therefore,the decreasing order of basicity is $(III) > (II) > (I) > (IV)$.

The decreasing order of basicity of the following amines is:
$(I)$ Aniline
$(II)$ Pyridine
$(III)$ Cyclohexylamine
$(IV)$ Pyrrole

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The decreasing order of basicity of the following amines is:$(I)$ Aniline$(II)$ Pyridine$(III)$ Cyclohexylamine$(IV)$ Pyrrole