The decreasing order of boiling points of the | vedclass

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(A) The boiling point of alkanes depends on the molecular mass and the extent of branching.As the molecular mass increases,the boiling point increases

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$(a) > (e) > (c) > (b) > (d)$

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(A) The boiling point of alkanes depends on the molecular mass and the extent of branching.As the molecular mass increases,the boiling point increases.For isomers,the boiling point decreases with an increase in branching due to a decrease in surface area.Heptane $(C_7H_{16})$: $371.4 \ K$Hexane $(C_6H_{14})$: $341.9 \ K$$2-$Methylbutane $(C_5H_{12})$: $300.9 \ K$Butane $(C_4H_{10})$: $272.4 \ K$$2-$Methylpropane $(C_4H_{10})$: $261 \ K$Comparing these values,the decreasing order is: $(a) > (e) > (c) > (b) > (d)$.

The decreasing order of boiling points of the following alkanes is:
$(a)$ Heptane
$(b)$ Butane
$(c)$ $2-$methylbutane
$(d)$ $2-$methylpropane
$(e)$ Hexane
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The decreasing order of boiling points of the following alkanes is:$(a)$ Heptane$(b)$ Butane$(c)$ $2-$methylbutane$(d)$ $2-$methylpropane$(e)$ HexaneChoose the correct answer from the options given below: