The decreasing order of stability of the foll | vedclass

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Question

(A) The stability of a carbanion is directly proportional to the electron-withdrawing group $(EWG)$ effect and inversely proportional to the electron-

Vedclass · Accepted Answer

$Q > R > S > P$

Vedclass · Answer

(A) The stability of a carbanion is directly proportional to the electron-withdrawing group $(EWG)$ effect and inversely proportional to the electron-releasing group $(ERG)$ effect.In the given anions:$Q$ has a $-CHO$ group,which is a strong $EWG$ ($-M$ effect).$R$ has a $-Cl$ group,which is an $EWG$ ($-I$ effect).$S$ has a $-CH_3$ group,which is an $ERG$ ($+I$ and hyperconjugation).$P$ has a $-OCH_3$ group,which is a strong $ERG$ ($+M$ effect).Therefore,the order of stability is $Q > R > S > P$.

The decreasing order of stability of the following anions is:

Similar Questions

Which of the following orders of rotation barrier about the $C=C$ bond,as indicated in the structures $(I)$,$(II)$,and $(III)$,is correct?

Which type of the overlap of orbitals is involved in hyperconjugation?

For the compound $R-CH=CH_2$,what is the order of the hyperconjugation effect for the group $R$,where $R$ is $CH_3-$,$CH_3CH_2-$,or $(CH_3)_2CH-$?

The decreasing order of stability of the following anions is:
$(P)$ $p-OCH_3-C_6H_4-CH_2^-$
$(Q)$ $p-CHO-C_6H_4-CH_2^-$
$(R)$ $p-Cl-C_6H_4-CH_2^-$
$(S)$ $p-CH_3-C_6H_4-CH_2^-$

Define the electromeric effect and describe its types.

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