The deflection in a moving coil galvanometer is reduced to half when it is shunted with a $40 \Omega$ coil. The resistance of the galvanometer is (in $\Omega$)

Explain the difficulties encountered when using a galvanometer directly as an ammeter.

The current flowing through a coil of resistance $900 \, \Omega$ is to be reduced by $90 \, \%$. What value of shunt should be connected across the coil in $\Omega$?

To convert a $800\, mV$ range millivoltmeter of resistance $40\,\Omega$ into an ammeter of $100\, mA$ range,the resistance to be connected as a shunt is .............. $\Omega$.

$A$ galvanometer of resistance $20 \,\Omega$ is to be converted into an ammeter of range $1 \, A$. If a current of $1 \, mA$ produces full scale deflection,the shunt required for the purpose is ................ $\Omega $.

The deflection in a galvanometer falls to $\left(\frac{1}{4}\right)^{th}$ of its initial value when it is shunted by a resistor of $3 \Omega$. If an additional shunt of $2 \Omega$ is connected in parallel to the earlier shunt,the deflection in the galvanometer falls to: