The deflection in a moving coil galvanometer falls from $25$ divisions to $5$ divisions when a shunt of $24\ \Omega$ is applied. The resistance of the galvanometer coil will be: (in $\Omega$)

How are a voltmeter and an ammeter connected in a circuit? Explain.

$A$ moving coil galvanometer has a coil with $175$ turns and an area of $1 \, cm^2$. It uses a torsion band with a torsion constant of $10^{-6} \, N \cdot m/rad$. The coil is placed in a magnetic field $B$ parallel to its plane. The coil deflects by $10^{\circ}$ for a current of $1 \, mA$. The value of $B$ (in Tesla) is approximately:

$A$ small cylindrical soft iron piece is kept in a galvanometer so that

The resistance of a galvanometer is $90\, \Omega$. If only $10\%$ of the main current is to flow through the galvanometer,how should a resistor be connected and what should be its value?

When a shunt of $4\,\Omega$ is attached to a galvanometer,the deflection reduces to $\frac{1}{5}$th of its initial value. If an additional shunt of $4\,\Omega$ is attached in parallel to the first,what will be the new deflection?