The dehydration of 2-methylbutanol with conc. | vedclass

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Question

(C) $1.$ The dehydration of $2-methylbutanol$ $(CH_3CH_2CH(CH_3)CH_2OH)$ with conc. $H_2SO_4$ proceeds via the formation of a carbocation intermediate

Vedclass · Accepted Answer

$2-methylbut-2-ene$ as major product

Vedclass · Answer

(C) $1.$ The dehydration of $2-methylbutanol$ $(CH_3CH_2CH(CH_3)CH_2OH)$ with conc. $H_2SO_4$ proceeds via the formation of a carbocation intermediate.$2.$ Initially,a primary carbocation is formed,which undergoes a $1,2-hydride$ shift to form a more stable tertiary carbocation $(CH_3CH_2C^+(CH_3)CH_3)$.$3.$ According to Saytzeff's rule,the more substituted alkene is the major product.$4.$ Elimination of a proton from the tertiary carbocation yields $2-methylbut-2-ene$ $(CH_3CH=C(CH_3)CH_3)$ as the major product.

The dehydration of $2-methylbutanol$ with conc. $H_2SO_4$ gives:

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