(B) The molar volume $V_m$ is calculated as $V_m = \frac{\text{Molar mass}}{\text{density}} = \frac{27}{0.3} = 90 \ L/mol$.The compressibility factor

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

$A$ behaves non-ideally with positive deviation

(B) The molar volume $V_m$ is calculated as $V_m = \frac{\text{Molar mass}}{\text{density}} = \frac{27}{0.3} = 90 \ L/mol$.The compressibility factor $Z$ is given by $Z = \frac{P V_m}{R T}$.Using $R = 0.0821 \ L \ atm \ K^{-1} \ mol^{-1}$,we get $Z = \frac{1 \times 90}{0.0821 \times 750} \approx 1.46$.Since $Z > 1$,the gas $A$ shows positive deviation from ideal behavior.

Class 11 Chemistry States of Matter Real gases and Vander waal’s equation

Medium

The density of a gas $A$ at $1 \ atm$ and $750 \ K$ is $0.3 \ g/L$. If the molar mass of $A$ is $27 \ g/mol$,then choose the correct statement -

A
$A$ behaves ideally
B
$A$ behaves non-ideally with positive deviation
C
$A$ behaves non-ideally with negative deviation
D
$A$ can be liquefied by applying pressure at $750 \ K$.

Explore More

Browse All

Question Bank

All Subjects

Class 11 Questions

Class 11

Chemistry Questions

Chapter

States of Matter

Subtopic

Real gases and Vander waal’s equation

The compressibility factor $(Z)$ of one mole of a van der Waals' gas of negligible '$a$' value is

MediumWBJEE 2014

View Solution

What is the compressibility factor of a gas at high pressure?

Difficult

View Solution

For $1$ mol of a real gas kept at constant temperature $T$,the graph of $PV$ vs $P$ intersects the $PV$ axis at $20$. Hence,the temperature $T$ is ($R$ = universal gas constant).

Medium

View Solution

The term that accounts for intermolecular force in Van der Waals equation for non-ideal gas is

Medium

View Solution

$A$ gas deviates from ideal behaviour at a high pressure because its molecules

MediumKCET 2008

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

The density of a gas $A$ at $1 \ atm$ and $750 \ K$ is $0.3 \ g/L$. If the molar mass of $A$ is $27 \ g/mol$,then choose the correct statement -

Similar Questions

The compressibility factor $(Z)$ of one mole of a van der Waals' gas of negligible '$a$' value is

What is the compressibility factor of a gas at high pressure?

For $1$ mol of a real gas kept at constant temperature $T$,the graph of $PV$ vs $P$ intersects the $PV$ axis at $20$. Hence,the temperature $T$ is ($R$ = universal gas constant).

The term that accounts for intermolecular force in Van der Waals equation for non-ideal gas is

$A$ gas deviates from ideal behaviour at a high pressure because its molecules

Vedclass Test Series

Exam Paper Generator

Online Exam Module