The density of a monobasic strong acid (Molar | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) For a monobasic acid,the reaction with $NaOH$ is: $HA + NaOH \rightarrow NaA + H_2O$.Since the acid is monobasic,$1 \ mol$ of acid reacts with $1

Vedclass · Accepted Answer

$12$

Vedclass · Answer

(B) For a monobasic acid,the reaction with $NaOH$ is: $HA + NaOH ightarrow NaA + H_2O$.Since the acid is monobasic,$1 \ mol$ of acid reacts with $1 \ mol$ of $NaOH$.Millimoles of $NaOH = M 	imes V(mL) = 0.24 	imes 25 = 6 \ mmol$.Therefore,millimoles of acid required $= 6 \ mmol$.Mass of acid $= 	ext{moles} 	imes 	ext{molar mass} = 6 	imes 10^{-3} \ mol 	imes 24.2 \ g \ mol^{-1} = 0.1452 \ g$.Given density $d = 1.21 \ kg \ L^{-1} = 1.21 \ g \ mL^{-1}$.Volume of acid solution $V = \frac{	ext{mass}}{	ext{density}} = \frac{0.1452 \ g}{1.21 \ g \ mL^{-1}} = 0.12 \ mL$.Converting to the required format: $0.12 \ mL = 12 	imes 10^{-2} \ mL$.

The density of a monobasic strong acid (Molar mass $24.2 \ g \ mol^{-1}$) is $1.21 \ kg \ L^{-1}$. The volume of its solution required for the complete neutralization of $25 \ mL$ of $0.24 \ M \ NaOH$ is $.............. \times 10^{-2} \ mL$ (Nearest integer).

Similar Questions

To change the strength of $25 \, mL$ of $0.15 \, M$ $HCl$ to $0.1 \, M$,the quantity of water that is to be added is.......$mL$

If $25 \ mL$ of a $H_2SO_4$ solution is neutralized by $32.63 \ mL$ of $0.164 \ M \ NaOH$ solution,what is the molarity of the $H_2SO_4$ solution (in $M$)?

Hydrochloric acid solutions $A$ and $B$ have concentrations of $0.5 \,N$ and $0.1 \,N$ respectively. The volumes of solutions $A$ and $B$ required to make $2 \,L$ of $0.2 \,N$ hydrochloric acid are:

The concentration of a $100 \ mL$ solution containing $X \ g$ of $Na_2CO_3$ (molecular weight $= 106$) is $Y \ M$. The values of $X$ and $Y$ are respectively.

To neutralize completely $20 \ mL$ of $0.1 \ M$ aqueous solution of phosphorous acid $(H_3PO_3)$,the volume of $0.1 \ M$ aqueous $KOH$ solution required is .......... $mL$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module