The diagonals of a rhombus are 12 cm and 16 | vedclass

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(C) Let the diagonals of the rhombus be $d_1 = 12 \ cm$ and $d_2 = 16 \ cm$.In a rhombus,the diagonals bisect each other at right angles $(90^{\circ})

Vedclass · Accepted Answer

$10$

Vedclass · Answer

(C) Let the diagonals of the rhombus be $d_1 = 12 \ cm$ and $d_2 = 16 \ cm$.In a rhombus,the diagonals bisect each other at right angles $(90^{\circ})$.This forms four right-angled triangles with legs equal to half the lengths of the diagonals.Leg $1 = \frac{d_1}{2} = \frac{12}{2} = 6 \ cm$.Leg $2 = \frac{d_2}{2} = \frac{16}{2} = 8 \ cm$.The side of the rhombus acts as the hypotenuse of these right-angled triangles.Using the Pythagorean theorem: $	ext{Side} = \sqrt{6^2 + 8^2} = \sqrt{36 + 64} = \sqrt{100} = 10 \ cm$.

The diagonals of a rhombus are $12 \ cm$ and $16 \ cm$. The length of one side is.......$cm$

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