The diagram below shows electric field lines | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The electric field $E$ is related to the potential $V$ by the relation $E = -\frac{dV}{dx}$.This implies that the magnitude of the electric field

Vedclass · Accepted Answer

Vedclass · Answer

(B) The electric field $E$ is related to the potential $V$ by the relation $E = -\frac{dV}{dx}$.This implies that the magnitude of the electric field is equal to the magnitude of the potential gradient,$|E| = |\frac{dV}{dx}|$.In the given diagram,the electric field lines are closer together near $X$ and become more spread out (uniform) as we move towards $Y$.This indicates that the electric field strength $|E|$ is higher near $X$ and decreases as we move towards $Y$.Since $|E| = |\frac{dV}{dx}|$,the slope of the potential $V$ versus distance $d$ graph must be steeper near $X$ and become less steep as we move towards $Y$.Among the given options,the graph in option $B$ shows a steep decrease in $V$ near $X$ (high slope) and a shallower decrease as we move towards $Y$ (lower slope),which correctly represents the variation of potential.

The diagram below shows electric field lines in a region of space. Which of the following diagrams best shows the variation with distance $d$ of the potential $V$ along the line $XY$ as we move from $X$ to $Y$?

Similar Questions

Write the relation between electric field and electrostatic potential.

The electric potential $V$ at any point $(x, y, z)$ (all in metres) in space is given by $V = 4x^2 \text{ volt}$. The electric field at the point $(1 \text{ m}, 0, 2 \text{ m})$ in $\text{volt/metre}$ is

Assume that an electric field $\overrightarrow{E} = 30x^2 \hat{i}$ exists in space. Then the potential difference $V_A - V_O$,where $V_O$ is the potential at the origin and $V_A$ is the potential at $x = 2 \, m$,is: (in $, V$)

What is potential gradient?

The potential difference between two parallel plates is $10^4 \,V$. If the plates are separated by $0.5 \,cm$, the force on an electron between the plates is

Vedclass Test Series

Exam Paper Generator

Online Exam Module