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(A) From Hooke's Law,stress $F = Y \cdot 	ext{strain} = Y \cdot (X/L)$,where $Y$ is Young's modulus and $L$ is the original length.Thus,$X = (F \cdot

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$T_1 > T_2$

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(A) From Hooke's Law,stress $F = Y \cdot 	ext{strain} = Y \cdot (X/L)$,where $Y$ is Young's modulus and $L$ is the original length.Thus,$X = (F \cdot L) / Y$.The slope of the $F-X$ graph is $F/X = Y/L$.As temperature increases,the Young's modulus $Y$ of a material generally decreases.In the given graph,the slope of the line for $T_1$ is less than the slope of the line for $T_2$ (i.e.,$	ext{slope}_{T_1} Since $	ext{slope} = Y/L$,this implies $Y_{T_1} Since Young's modulus decreases with an increase in temperature,a lower Young's modulus corresponds to a higher temperature.Therefore,$T_1 > T_2$.

The diagram below shows the change in the length $X$ of a thin uniform wire caused by the application of stress $F$ at two different temperatures $T_1$ and $T_2$. The variation shown suggests that

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