The difference in the oxidation numbers of th | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The structure of $Na_2S_4O_6$ is shown below:$Na^+O^--S(=O)_2-S-S-S(=O)_2-O^-Na^+$In $Na_2S_4O_6$ (sodium tetrathionate),there are two types of su

Vedclass · Accepted Answer

$5$

Vedclass · Answer

(A) The structure of $Na_2S_4O_6$ is shown below:$Na^+O^--S(=O)_2-S-S-S(=O)_2-O^-Na^+$In $Na_2S_4O_6$ (sodium tetrathionate),there are two types of sulphur atoms:$1$. The two terminal sulphur atoms are bonded to three oxygen atoms (two via double bonds and one via a single bond) and one sulphur atom. Their oxidation number is calculated as $+5$.$2$. The two central sulphur atoms are bonded only to two other sulphur atoms. Since the electronegativity of identical atoms is the same,their oxidation number is $0$.The difference in the oxidation numbers of the two types of sulphur atoms is $|5 - 0| = 5$.

The difference in the oxidation numbers of the two types of sulphur atoms in $Na_2S_4O_6$ is

Similar Questions

What is the oxidation state of nitrogen in $N_3H$?

What is the oxidation state of oxygen in $O_2^{2-}$ ion?

Which of the following involves the transfer of five electrons?

The oxidation state of phosphorus in hypophosphoric acid is $+......$

What are the oxidation numbers of nitrogen in $NH_4NO_3$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module