The differential equation representing the family of curves $x \sin x + y^3 = 4ax$ is
- A$\frac{dy}{dx} = \frac{y^3 + x^2 \cos x}{3xy^2}$
- B$\frac{dy}{dx} = \frac{y^3 - x^2 \cos x}{3xy^2}$
- C$\frac{dy}{dx} = \frac{y^3 - x^2 \cos x}{3xy}$
- D$\frac{dy}{dx} = \frac{y^3 - x^2 \cos x}{3x^2y}$
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