The dimension of magnetic field in M, L, T an | vedclass

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Question

(C) The magnetic force $F$ on a charge $q$ moving with velocity $v$ in a magnetic field $B$ is given by the Lorentz force formula: $F = qvB \sin 	het

Vedclass · Accepted Answer

$M^1T^{-1}C^{-1}$

Vedclass · Answer

(C) The magnetic force $F$ on a charge $q$ moving with velocity $v$ in a magnetic field $B$ is given by the Lorentz force formula: $F = qvB \sin 	heta$. Considering dimensions,we have $[F] = [q][v][B]$. The dimensions are: $[F] = MLT^{-2}$,$[q] = C$,and $[v] = LT^{-1}$. Rearranging for $B$,we get: $[B] = \frac{[F]}{[q][v]} = \frac{MLT^{-2}}{C \cdot LT^{-1}}$. Simplifying the expression: $[B] = M \cdot L^1 L^{-1} \cdot T^{-2} T^1 \cdot C^{-1} = MT^{-1}C^{-1}$.

The dimension of magnetic field in $M, L, T$ and $C$ (coulomb) is given as:

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