The dipole moment of each molecule of a param | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The intensity of magnetization $I$ is defined as the net magnetic dipole moment per unit volume.For maximum magnetization,all molecular dipoles mu

Vedclass · Accepted Answer

$3 	imes 10^3 \, A/m$

Vedclass · Answer

(A) The intensity of magnetization $I$ is defined as the net magnetic dipole moment per unit volume.For maximum magnetization,all molecular dipoles must be aligned in the same direction.Given:Dipole moment of each molecule,$\mu = 1.5 	imes 10^{-23} \, A \cdot m^2$Number of molecules per unit volume,$n = \frac{N}{V} = 2 	imes 10^{26} \, m^{-3}$The formula for intensity of magnetization is $I = n 	imes \mu$.Substituting the values:$I = (2 	imes 10^{26} \, m^{-3}) 	imes (1.5 	imes 10^{-23} \, A \cdot m^2)$$I = 3 	imes 10^3 \, A/m$.Thus,the maximum possible intensity of magnetization is $3 	imes 10^3 \, A/m$.

The dipole moment of each molecule of a paramagnetic gas is $1.5 \times 10^{-23} \, A \cdot m^2$. The temperature of the gas is $27 \, ^\circ C$ and the number of molecules per unit volume is $2 \times 10^{26} \, m^{-3}$. The maximum possible intensity of magnetization in the gas will be:

Similar Questions

Oersted is a unit of

What does the magnetic susceptibility of a material show?

Define magnetisation $(M)$ and give its unit and dimension.

$A$ solenoid of $500$ turns $/ m$ is carrying a current of $3 \ A$. Its core is made of iron which has a relative permeability of $5001$. The magnitude of magnetization is:

The magnetization of a bar magnet of length $5 \ cm$,cross-sectional area $2 \ cm^2$ and net magnetic moment $1 \ A \cdot m^2$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module