The displacement due to a wave moving in the | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The general equation for a wave traveling in the positive $x$-direction is given by $y = f(x - vt)$,where $v$ is the wave velocity.At $t = 0$,the

Vedclass · Accepted Answer

$0.5$

Vedclass · Answer

(A) The general equation for a wave traveling in the positive $x$-direction is given by $y = f(x - vt)$,where $v$ is the wave velocity.At $t = 0$,the equation is $y = f(x) = \frac{1}{1 + x^2}$.At $t = 2$ seconds,the equation is $y = f(x - v(2)) = \frac{1}{1 + (x - 2v)^2}$.Comparing this with the given equation at $t = 2$,which is $y = \frac{1}{1 + (x - 1)^2}$,we can equate the terms inside the square:$x - 2v = x - 1$$2v = 1$$v = 0.5 \ m/s$.Therefore,the velocity of the wave is $0.5 \ m/s$.

The displacement due to a wave moving in the positive $x$-direction is given by $y = \frac{1}{(1 + x^2)}$ at time $t = 0$ and by $y = \frac{1}{[1 + (x - 1)^2]}$ at $t = 2$ seconds,where $x$ and $y$ are in metres. The velocity of the wave in $m/s$ is

Similar Questions

If the wave equation is $y = 0.08 \sin \frac{2\pi}{\lambda} (200t - x)$,then the velocity of the wave will be:

The path difference between two waves $Y_1 = a_1 \sin \left(\omega t - \frac{2 \pi x}{\lambda}\right)$ and $Y_2 = a_2 \cos \left(\omega t - \frac{2 \pi x}{\lambda} + \phi\right)$ is

Write the definition,unit,and dimensional formula of amplitude.

Which of the following is different from others?

The two waves represented by $y_1 = a \sin(\omega t)$ and $y_2 = b \cos(\omega t)$ have a phase difference of

Vedclass Test Series

Exam Paper Generator

Online Exam Module