The displacement equations of sound waves pro | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The given equations are $y_1 = 5 \sin(400 \pi t)$ and $y_2 = 8 \sin(408 \pi t)$.Comparing these with the standard equation $y = A \sin(\omega t)$,

Vedclass · Accepted Answer

$240$

Vedclass · Answer

(D) The given equations are $y_1 = 5 \sin(400 \pi t)$ and $y_2 = 8 \sin(408 \pi t)$.Comparing these with the standard equation $y = A \sin(\omega t)$, we get angular frequencies $\omega_1 = 400 \pi 	ext{ rad/s}$ and $\omega_2 = 408 \pi 	ext{ rad/s}$.The frequencies of the two waves are $f_1 = \frac{\omega_1}{2 \pi} = \frac{400 \pi}{2 \pi} = 200 	ext{ Hz}$ and $f_2 = \frac{\omega_2}{2 \pi} = \frac{408 \pi}{2 \pi} = 204 	ext{ Hz}$.The beat frequency is the difference between the two frequencies: $f_b = |f_2 - f_1| = |204 - 200| = 4 	ext{ beats per second}$.To find the number of beats per minute, we multiply the beat frequency by $60 	ext{ seconds}$:$	ext{Beats per minute} = 4 	imes 60 = 240 	ext{ beats/min}$.

The displacement equations of sound waves produced by two sources are given by $y_1 = 5 \sin(400 \pi t)$ and $y_2 = 8 \sin(408 \pi t)$, where $t$ is time in seconds. If the waves are produced simultaneously, the number of beats produced per minute is

Similar Questions

What is the chemical nature of alane?

$A$ regular polygon of $n$ sides has $170$ diagonals,then $n$ is equal to

In which of the following reactions does $H_2O_2$ act as a reducing agent?

The values of $a$ and $b$,so that the function $f(x) = \begin{cases} x + a \sqrt{2} \sin x, & 0 \le x \le \frac{\pi}{4} \\ 2x \cot x + b, & \frac{\pi}{4} < x \le \frac{\pi}{2} \\ a \cos 2x - b \sin x, & \frac{\pi}{2} < x \le \pi \end{cases}$ is continuous for $0 \le x \le \pi$,are respectively:

If the lines $4x + 3y - 1 = 0$,$x - y + 5 = 0$ and $kx + 5y - 3 = 0$ are concurrent,then $k$ is equal to:

Vedclass Test Series

Exam Paper Generator

Online Exam Module