The displacement-time graph of two moving par | vedclass

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(D) By definition,the slope of a displacement-time graph represents the velocity of the particle.$v = 	an 	heta$Given the angles $	heta_1 = 30^{\ci

Vedclass · Accepted Answer

$1: \sqrt{3}$

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(D) By definition,the slope of a displacement-time graph represents the velocity of the particle.$v = 	an 	heta$Given the angles $	heta_1 = 30^{\circ}$ and $	heta_2 = 45^{\circ}$.The ratio of their velocities is given by:$\frac{v_1}{v_2} = \frac{	an 	heta_1}{	an 	heta_2}$Substituting the values:$\frac{v_1}{v_2} = \frac{	an 30^{\circ}}{	an 45^{\circ}}$Since $	an 30^{\circ} = \frac{1}{\sqrt{3}}$ and $	an 45^{\circ} = 1$,we get:$\frac{v_1}{v_2} = \frac{1/\sqrt{3}}{1} = \frac{1}{\sqrt{3}}$Thus,the ratio is $1: \sqrt{3}$.

The displacement-time graph of two moving particles makes angles of $30^{\circ}$ and $45^{\circ}$ with the time axis ($X$-axis). The ratio of their velocities is

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