The dissociation constants of two acids HA_1 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The relative strength of two acids is given by the ratio of the square roots of their dissociation constants $(K_a)$: $	ext{Relative Strength} =

Vedclass · Accepted Answer

$4 : 1$

Vedclass · Answer

(B) The relative strength of two acids is given by the ratio of the square roots of their dissociation constants $(K_a)$: $	ext{Relative Strength} = \sqrt{\frac{K_{a1}}{K_{a2}}} = \sqrt{\frac{3.0 	imes 10^{-4}}{1.8 	imes 10^{-5}}} = \sqrt{\frac{30 	imes 10^{-5}}{1.8 	imes 10^{-5}}} = \sqrt{\frac{30}{1.8}} = \sqrt{16.66} \approx 4.08 \approx 4$. Thus,the ratio of the strengths of $HA_1$ to $HA_2$ is $4 : 1$.

The dissociation constants of two acids $HA_1$ and $HA_2$ are $3.0 \times 10^{-4}$ and $1.8 \times 10^{-5}$ respectively. The relative strengths of the acids will be

Similar Questions

What do you understand by the term 'auto-protolysis' of water? What is its significance?

Ammonia is a Lewis base because it is

Which of the following is not a Lewis acid?

Explain the statement: "$NH_3$ acts as both a Lewis base and a Brønsted-Lowry base,whereas $BF_3$ acts only as a Lewis acid but not as a Brønsted-Lowry acid."

Which of the following ions is the most basic?

Vedclass Test Series

Exam Paper Generator

Online Exam Module