The distance v of the real image formed by a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) For a convex lens,the lens formula is given by $\frac{1}{f} = \frac{1}{v} - \frac{1}{u}$,where $f$ is the focal length,$v$ is the image distance,a

Vedclass · Accepted Answer

Vedclass · Answer

(D) For a convex lens,the lens formula is given by $\frac{1}{f} = \frac{1}{v} - \frac{1}{u}$,where $f$ is the focal length,$v$ is the image distance,and $u$ is the object distance.Using the sign convention for a real image,$u$ is negative $(-u)$ and $v$ is positive. The formula becomes $\frac{1}{f} = \frac{1}{v} - \frac{1}{-u}$,which simplifies to $\frac{1}{v} = \frac{1}{f} - \frac{1}{u}$.As $u$ increases from $f$ to $\infty$,the value of $\frac{1}{u}$ decreases,which means $\frac{1}{v}$ increases,and therefore $v$ decreases.Specifically,when $u = f$,$v = \infty$,and as $u 	o \infty$,$v 	o f$. This relationship represents a hyperbolic curve where $v$ decreases as $u$ increases,which is correctly depicted in option $D$.

The distance $v$ of the real image formed by a convex lens is measured for various object distances $u$. $A$ graph is plotted between $v$ and $u$. Which one of the following graphs is correct?

Similar Questions

The image of an illuminated square is obtained on a screen with the help of a converging lens. The distance of the square from the lens is $40\,cm$. The area of the image is $9$ times that of the square. The focal length of the lens is........$cm$.

An object placed $10 \ cm$ in front of a lens has an image $20 \ cm$ behind the lens. What is the power of the lens (in dioptres)?

$A$ convex lens is dipped in a liquid whose refractive index is equal to the refractive index of the lens material. Then its focal length will

The distance between an object and its image produced by a converging lens is $0.72 \ m$. The magnification is $2$. What will be the magnification when the object is moved by $0.04 \ m$ towards the lens?

An optician prescribes a corrective lens of power $+2.0 \,D$. The focal length of the required convex lens is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module