(A) The distance between two successive minima is equal to the wavelength $\lambda$. Therefore, $\lambda = 2.7 \ m$.Frequency $f$ is defined as the nu

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(A) The distance between two successive minima is equal to the wavelength $\lambda$. Therefore, $\lambda = 2.7 \ m$.Frequency $f$ is defined as the number of waves passing a point per unit time.Given that $5$ crests pass in $15.0 \ s$, the frequency is $f = \frac{5}{15} = \frac{1}{3} \ s^{-1}$.The speed of the wave $v$ is given by the relation $v = f \lambda$.Substituting the values, $v = \frac{1}{3} \times 2.7 = 0.9 \ m \ s^{-1}$.

Class 11 Physics Waves and Sound Wave Equation and Characteristics of Waves

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The distance between two successive minima of a transverse wave is $2.7 \ m$. Five crests of the wave pass a given point along the direction of travel every $15.0 \ s$. The speed of the wave is (in $m \ s^{-1}$)

TS EAMCET 2022 All TS EAMCET

A
$0.9$
B
$1.2$
C
$0.5$
D
$2.4$

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Wave Equation and Characteristics of Waves

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The distance between two successive minima of a transverse wave is $2.7 \ m$. Five crests of the wave pass a given point along the direction of travel every $15.0 \ s$. The speed of the wave is (in $m \ s^{-1}$)

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