The distance-time graph of a particle at time | vedclass

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Question

(A) The slope of the distance-time $(s-t)$ graph represents the velocity of the particle.Initial velocity at time $t$ is $v_i = 	an(45^{\circ}) = 1 \

Vedclass · Accepted Answer

$\sqrt{3}-1$

Vedclass · Answer

(A) The slope of the distance-time $(s-t)$ graph represents the velocity of the particle.Initial velocity at time $t$ is $v_i = 	an(45^{\circ}) = 1 \, m/s$.Final velocity after one second is $v_f = 	an(60^{\circ}) = \sqrt{3} \, m/s$.The average acceleration is defined as the change in velocity divided by the time interval:$a_{av} = \frac{v_f - v_i}{\Delta t}$.Substituting the values:$a_{av} = \frac{\sqrt{3} - 1}{1} = (\sqrt{3} - 1) \, m/s^2$.

The distance-time graph of a particle at time $t$ makes an angle of $45^{\circ}$ with the time axis. After one second,it makes an angle of $60^{\circ}$ with the time axis. What is the average acceleration of the particle?

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