The dual of $\left(x^{\prime} \vee y^{\prime}\right) = x \wedge y$ is
- A$\left(x^{\prime} \wedge y^{\prime}\right) = x \vee y$
- B$\left(x^{\prime} \vee y^{\prime}\right) = x \wedge y$
- C$\left(x^{\prime} \wedge y^{\prime}\right) = x \wedge y$
- DNone of the above
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