The efficiency of a Carnot engine is 0.6. It | vedclass

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(D) The efficiency $\eta$ of a Carnot engine is given by $\eta = 1 - \frac{Q_r}{Q_i}$,where $Q_r$ is the heat rejected and $Q_i$ is the heat input.Giv

Vedclass · Accepted Answer

$30$

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(D) The efficiency $\eta$ of a Carnot engine is given by $\eta = 1 - \frac{Q_r}{Q_i}$,where $Q_r$ is the heat rejected and $Q_i$ is the heat input.Given $\eta = 0.6$ and $Q_r = 20 \ J$.Substituting the values: $0.6 = 1 - \frac{20}{Q_i}$.Rearranging the equation: $\frac{20}{Q_i} = 1 - 0.6 = 0.4$.Thus,$Q_i = \frac{20}{0.4} = 50 \ J$.The work done $W$ is given by $W = Q_i - Q_r$.$W = 50 \ J - 20 \ J = 30 \ J$.

The efficiency of a Carnot engine is $0.6$. It rejects a total of $20 \ J$ of heat. The work done by the engine is .... $J$.

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