(C) The temperatures of the reservoirs are given as $T_{1} = 100^{\circ}C$ and $T_{2} = -23^{\circ}C$.First,convert these temperatures to the Kelvin s

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(C) The temperatures of the reservoirs are given as $T_{1} = 100^{\circ}C$ and $T_{2} = -23^{\circ}C$.First,convert these temperatures to the Kelvin scale:$T_{1} = 100 + 273 = 373\,K$$T_{2} = -23 + 273 = 250\,K$The efficiency $\eta$ of a Carnot engine is given by the formula:$\eta = 1 - \frac{T_{2}}{T_{1}}$Substituting the values:$\eta = \frac{T_{1} - T_{2}}{T_{1}} = \frac{373 - 250}{373}$

Class 11 Physics Thermodynamics Heat Engine and Carnot Cycle

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The efficiency of a Carnot engine operating with reservoir temperatures of $100\,^{\circ}C$ and $-23\,^{\circ}C$ will be

AIPMT 1997 All AIPMT

A
$\frac{373+250}{373}$
B
$\frac{100+23}{100}$
C
$\frac{373-250}{373}$
D
$\frac{100-23}{100}$

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The efficiency of a Carnot engine operating with reservoir temperatures of $100\,^{\circ}C$ and $-23\,^{\circ}C$ will be

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