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(B) The efficiency of aerobic respiration is calculated by comparing the energy captured in $ATP$ molecules to the total energy released from the oxid

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$45$

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(B) The efficiency of aerobic respiration is calculated by comparing the energy captured in $ATP$ molecules to the total energy released from the oxidation of one molecule of glucose.One molecule of glucose releases approximately $686 	ext{ kcal}$ of energy upon complete oxidation.The synthesis of $38$ $ATP$ molecules stores approximately $38 	imes 8.1 	ext{ kcal} = 307.8 	ext{ kcal}$ of energy.Efficiency $= (	ext{Energy stored in } ATP / 	ext{Total energy released}) 	imes 100$Efficiency $= (307.8 / 686) 	imes 100 \approx 45\%$.

The efficiency of aerobic respiration is approximately (in $\%$)

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