The electric current i in the circuit shown i | vedclass

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(D) According to Kirchhoff's Current Law $(KCL)$, the sum of currents entering a junction equals the sum of currents leaving it.At junction $A$:$i_1 =

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$4$

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(D) According to Kirchhoff's Current Law $(KCL)$, the sum of currents entering a junction equals the sum of currents leaving it.At junction $A$:$i_1 = 3 	ext{ A} + 2 	ext{ A} = 5 	ext{ A}$At junction $B$:The current $i_1$ enters the junction, and $2 	ext{ A}$ leaves it. Let $i_2$ be the current flowing towards junction $C$.$i_1 = 2 	ext{ A} + i_2$$5 	ext{ A} = 2 	ext{ A} + i_2 \implies i_2 = 3 	ext{ A}$At junction $C$:The currents $i_2$ and $1 	ext{ A}$ enter the junction, and $i$ leaves it.$i = i_2 + 1 	ext{ A}$$i = 3 	ext{ A} + 1 	ext{ A} = 4 	ext{ A}$

The electric current $i$ in the circuit shown is (in $\text{ A}$)

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