The electric field part of an electromagnetic | vedclass

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(D) The given equation for the electric field is:$E = 3.1 \cos [ (1.8) y + (5.4 	imes 10^8) t ] \hat{i}$  .......... $(i)$Comparing this with the sta

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$3.5$

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(D) The given equation for the electric field is:$E = 3.1 \cos [ (1.8) y + (5.4 	imes 10^8) t ] \hat{i}$  .......... $(i)$Comparing this with the standard wave equation:$E = E_0 \cos (ky + \omega t)$  .......... $(ii)$We identify the wave number $k$ as:$k = 1.8 \, rad \, m^{-1}$The relationship between wavelength $\lambda$ and wave number $k$ is given by:$\lambda = \frac{2 \pi}{k}$Substituting the value of $k$ and using $\pi \approx 3.14159$:$\lambda = \frac{2 	imes 3.14159}{1.8} \approx 3.49 \, m$Rounding to the nearest provided option,we get:$\lambda \approx 3.5 \, m$

The electric field part of an electromagnetic wave in vacuum is
$E = 3.1 \, N C^{-1} \cos [ (1.8 \, rad \, m^{-1}) y + (5.4 \times 10^8 \, rad \, s^{-1}) t ] \hat{i}$
The wavelength of this part of the electromagnetic wave is ...... $m$.

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The electric field part of an electromagnetic wave in vacuum is$E = 3.1 \, N C^{-1} \cos [ (1.8 \, rad \, m^{-1}) y + (5.4 \times 10^8 \, rad \, s^{-1}) t ] \hat{i}$The wavelength of this part of the electromagnetic wave is ...... $m$.