Class 12PhysicsElectric Potential and CapacitanceRelation between Electric Field and Potential and Potential Gradient
MediumThe electric potential $V$ is given as a function of distance $x$ $(m)$ by $V = (2x^2 + 10x - 9) \text{ V}$. The value of the electric field at $x = 1 \text{ m}$ is: (in $\text{ V/m}$)
- A$-20$
- B$6$
- C$-11$
- D$-14$
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