The electrode potential of M^{2+} / M for 3d- | vedclass

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Question

(D) The electrode potential $E^{\Theta}$ for the reduction of $M^{2+}$ to $M$ in the $3d$-series is generally negative,except for copper.Copper $(Cu)$

Vedclass · Accepted Answer

$Cu$

Vedclass · Answer

(D) The electrode potential $E^{\Theta}$ for the reduction of $M^{2+}$ to $M$ in the $3d$-series is generally negative,except for copper.Copper $(Cu)$ has a positive standard electrode potential $(E^{\Theta} = +0.34 \ V)$ because the high energy required to transform $Cu(s)$ to $Cu^{2+}(aq)$ (sum of enthalpy of atomization and ionization enthalpy) is not compensated by its hydration enthalpy.Therefore,the correct option is $D$.

The electrode potential of $M^{2+} / M$ for $3d$-series elements shows a positive value for which of the following?

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